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A cylinder of compressed gas that bears no label is supposed to contain either ethane or ethene. Combustion of the sample shows that 16 c m 3 of the gas require 48 c m 3 of oxygen for complete combustion. This shows that the gas is

Options

  1. Aonly ethane
  2. Bonly ethene
  3. C1:1 mixtures of two gases
  4. Dsome unknown mixture of the two gases

Correct answer

B. only ethene

Step-by-step solution

C x H y 1 vol 16 c m 3 + x + y 4 O 2 x + y 4 v o l 16 x + y 4 c m 3 → x C O 2 + y 2 H 2 O Now we have 16 x + y 4 = 48 or y = 4 Hence, the hydrocarbon is C 2 H 4 .

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