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NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice

For a given reaction, Δ H = 35 . 5 kJmo l - 1 and Δ S = 83 . 6 J k - 1 mo l - 1 . The reaction is spontaneous at (Assume that Δ H and Δ S do not vary with tempearature)

Options

  1. AT > 425 K
  2. BAll temperatures
  3. CT > 398 K
  4. DT < 525 K

Correct answer

A. T > 425 K

Step-by-step solution

As Both &#916; H and &#916; S are positive so to keep &#916; G = - ve High Temp is favourable so that process become spontaneous. &#916; G = &#916; H - T . &#916; S T = &#916; H &#916; S = 35.5 &#215; 1000 83.6 &#62; 424.6 K T &#62; 425K

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