NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice
The temperature coefficient of e.m.f of a cell can be given by:
Options
- A∂ E ∂ T P = Δ S n F
- B∂ E ∂ T P = E 2 - E 1 T 2 - T 1
- C∂ E ∂ T P = Δ Η n F + E · 1 T
- DAll of these
Correct answer
D. All of these
Step-by-step solution
Δ G = Δ H + T ∂ Δ G ∂ T P (Gibbs-Helmholz equation) Also, Δ G = Δ H - T Δ S ; and - Δ G = n F · E or - T Δ S = T ∂ Δ G ∂ T P = T - n F ∂ E ∂ T P or ∂ E ∂ T P = Δ S n F , similarly derive for other values.