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NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice

Calculate the increase in internal energy of system when 40 joule heat is supplied and the work done by a system is 8 joule

Options

  1. A25 J
  2. B30 J
  3. C32 J
  4. D28 J

Correct answer

C. 32 J

Step-by-step solution

q = 40 J w = - 8 J (work done by the system) Δ E = q + w = 40 - 8 = 32 J .

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