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The value of log 10 K for reaction, A ⇌ B ; is (Given : Δ r H 298 K 0 = − 54.07 k J m o l – 1 , Δ r S 288 K 0 = 10 J K – 1 m o l – 1 and R = 8.31 J K – 1 m o l – 1 , 2.303 × 8.314 × 298 = 5705 )

Correct answer

10

Step-by-step solution

log   K   =   ΔS o 2 .303   R − ΔH o 2 .303   RT = 10 2.303 × 8.314 − ( − 54.07 × 10 3 ) 2.303 × 8.314 × 298 = 10 × 298 5705 + 54070 5705 = 57050 5705 = 10

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