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The heat of neutralisation of a strong base and a strong acid is 13.7 kcal. The heat released when 0.7 mole HBr solution is added to 0.35 mole of KOH is

Options

  1. A5.425 kcal
  2. B13.7 kcal
  3. C4.795 kcal
  4. D8.795 kcal

Correct answer

C. 4.795 kcal

Step-by-step solution

For the neutralization between a strong and a strong base, equal number of moles of H + (from acid) and O ̄ H (from base) come out. For one mole of each following equation can be drawn So, 0.35 mole of H 2 O is produced. So, heat released = ( 0.35 × 13.7 ) k c a l = 4.795 k c a l

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