NTA Abhyas JEE Main2020MathematicsHyperbolaPractice
If e 1 and e 2 are the eccentricities of the ellipse x 2 18 + y 2 4 = 1 and the hyperbola x 2 9 - y 2 4 = 1 respectively and e 1 , e 2 is a point on the ellipse 15 x 2 + 3 y 2 = k , then the value of k is equal to
Options
- A16
- B17
- C15
- D14
Correct answer
A. 16
Step-by-step solution
e 1 = 1 - 4 18 = 7 9 = 7 3 e 1 = 1 + 4 9 = 13 9 = 13 3 Also, 15 e 1 2 + 3 e 2 2 = k ⇒ k = 15 7 9 + 3 13 9 ∴ k = 16