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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Experimental Physics

NTA Abhyas 2020 · Physics · Experimental Physics

In an experiment to determine the resistance of a galvanometer by...

In an experiment to determine the resistance of a galvanometer by half deflection method, the circuit shown is used. In one set of readings, if R=10ΩR = 10\text{Ω} and S=4ΩS = 4\text{Ω}, then the resistance of the galvanometer is

In an experiment to determine the resistance of a galvanometer by half deflection method, the circuit shown is used. In

Options

  1. A203Ω\dfrac{20}{3} \text{Ω}
  2. B403Ω\dfrac{40}{3} \text{Ω}
  3. C\dfrac{50}{3} \text{Ω}
  4. D\dfrac{70}{3} \text{Ω}

Correct answer

A. 203Ω\dfrac{20}{3} \text{Ω}

Step-by-step solution

In 1st case,&

I1=ER+G{I}_{1} = \dfrac{E}{R + G}

In 2nd case,

I2=ER+SGS+G{I}_{2} = \dfrac{E}{R + \dfrac{SG}{S + G}}

for half deflection,

I2G=12I1{I}_{2G} = \dfrac{1}{2}{I}_{1}

12ER+G=ER+SGS+GSS+G\dfrac{1}{2}\dfrac{E}{R + G} = \dfrac{E}{R + \dfrac{SG}{S + G}}\dfrac{S}{S + G}

⇒G=RSR−S⇒ G = \dfrac{RS}{R - S}

G=10×410−4=203ΩG = \dfrac{10 \times 4}{10 - 4} = \dfrac{20}{3}Ω

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