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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Thermal Properties of Matter

NTA Abhyas 2020 · Physics · Thermal Properties of Matter

Two electric lamps A and B radiate the same power. Their filaments...

Two electric lamps AA and BB radiate the same power. Their filaments have the same dimensions and have emissivities eA{e}_{A} and eB{e}_{B} respectively. Their surface temperatures are TA{T}_{A} and TB{T}_{B}. The ratio TATB\dfrac{{T}_{A}}{{T}_{B}} will be equal to

Options

  1. A(eBeA)1/4{( \dfrac{{e}_{B}}{{e}_{A}} )}^{1 / 4}
  2. B(eBeA)1/2{( \dfrac{{e}_{B}}{{e}_{A}} )}^{1 / 2}
  3. C(eAeB)1/2{( \dfrac{{e}_{A}}{{e}_{B}} )}^{1 / 2}
  4. D(eAeB)1/4{( \dfrac{{e}_{A}}{{e}_{B}} )}^{1 / 4}

Correct answer

A. (eBeA)1/4{( \dfrac{{e}_{B}}{{e}_{A}} )}^{1 / 4}

Step-by-step solution

The power radiated by a filament is P=eA(\sigmaT4) and (whereP = eA \left(\sigmaT^{4}\right) \text{ and } (where e =emissivity,σ=Stefan′sconstantandemissivity, \sigma = Stefan's constant and T =surfacetemperature)<br/>Here,surface temperature)<br />Here,eT^{4} =constantorconstant or{e}_{A} {T}_A^{4} = {e}_{B} {T}_B^{4}
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