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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Thermal Properties of Matter

NTA Abhyas 2020 · Physics · Thermal Properties of Matter

Ice starts forming in a lake where the water is at 0 ° C and the...

Ice starts forming in a lake where the water is at 0°C0 ° C and the ambient temperature is −10°C- 10 ° C. If the time taken for 11 cm of ice to be formed is 7hours7 hours, then the time taken for the thickness of ice to change from 11 cm to 22 cm is

Options

  1. A7hours7hours
  2. B14hours14hours
  3. C10.5hours10.5hours
  4. D21hours21hours

Correct answer

D. 21hours21hours

Step-by-step solution

If at some time& tt, the thickness of ice is& x and at time&t + dt,thethickenessis, the thickeness isx + dx,then</p><p>(ρAdx)Lfusion=kA(0−(−10))xdt, then</p><p>\left(ρAdx\right){L}_{fusion} = \dfrac{kA\left(0 - \left(-10\right)\right)}{x}dt

⇒∆t=ρLfusion20k(x22−x12)</p><p>⇒ ∆ t = \dfrac{ρ{L}_{fusion}}{20k}\left({x}_{2}^{2} - {x}_{1}^{2}\right)</p><p>⇒ ∆ t ∝ ( {x}_{2}^{2} - {x}_{1}^{2} )</p><p></p><p>⇒ ∆t∆t′=x22−x12(x′2)2−(x′1)2</p><p>\dfrac{∆ t}{∆ t '} = \dfrac{{x}_{2}^{2} - {x}_{1}^{2}}{\left(x{'}_{2}\right)2 - \left(x{'}_{1}\right)2}</p><p>⇒ 7∆t′=(12−02)(22−12)</p><p>\dfrac{7}{∆ t '} = \dfrac{( {1}^{2} - {0}^{2} )}{( {2}^{2} - {1}^{2} )}</p><p>⇒ ∆ t ' = 21hours</p></p>

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