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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Thermal Properties of Matter

NTA Abhyas 2020 · Physics · Thermal Properties of Matter

The spectral emissive power E _ λ for a body at temperature T _ 1...

The spectral emissive power Eλ{E}_{λ} for a body at temperature T1{T}_{1} is plotted against the wavelength (see figure) and area under the curve is found to be AA. At a different temperature T2{T}_{2} the area is found to be 9A9A. Then λ1/λ2={λ}_{1} / {λ}_{2} =

The spectral emissive power E _ λ for a body at temperature T _ 1 is plotted against the wavelength (see figure) and

Options

  1. A3
  2. B13\dfrac{1}{3}
  3. C13\dfrac{1}{\sqrt{3}}
  4. D3\sqrt{3}

Correct answer

D. 3\sqrt{3}

Step-by-step solution

E1E2=19=(T1T2)4\dfrac{E1}{E2} = \dfrac{1}{9} = \left(\dfrac{T1}{T2}\right)4

λ1T1=λ2T2⇒T1T2=λ2λ1{λ}_{1}{T}_{1} = {λ}_{2}{T}_{2} ⇒ \dfrac{T1}{T2} = \dfrac{\lambda2}{\lambda1}

19=(λ2λ1)4⇒λ2λ1=13\dfrac{1}{9} = \left(\dfrac{\lambda2}{\lambda1}\right)4 ⇒ \dfrac{\lambda2}{\lambda1} = \dfrac{1}{3}

λ1λ2=3\dfrac{\lambda1}{\lambda2} = \sqrt{3}
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