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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Thermal Properties of Matter

NTA Abhyas 2020 · Physics · Thermal Properties of Matter

The figure shows a system of two concentric spheres of radii r _ 1...

The figure shows a system of two concentric spheres of radii r1{r}_{1} and r2{r}_{2} and kept at temperatures T1{T}_{1} and T2{T}_{2}, respectively. The radial rate of flow of heat in a substance between the two concentric spheres is proportional to

The figure shows a system of two concentric spheres of radii r _ 1 and r _ 2 and kept at temperatures T _ 1 and T _ 2 ,

Options

  1. A\dfrac{{r}_{1} {r}_{2}}{\left({r}_{2} - {r}_{1}\right)}
  2. B(r2−r1)\left({r}_{2} - {r}_{1}\right)
  3. C(r2−r1)r1r2\left({r}_{2} - {r}_{1}\right){r}_{1}{r}_{2}
  4. Dln⁡(r2r1)\ln \left(\dfrac{\text{r}2}{\text{r}1}\right)

Correct answer

A. \dfrac{{r}_{1} {r}_{2}}{\left({r}_{2} - {r}_{1}\right)}

Step-by-step solution

For conduction from inner sphere to outer one,

dQ=−KAdTdr×(timedt)<br/><br/>or  and  and  and dQdt=−K×(4\pir2)dTdr\text{dQ} = - \text{KA} \dfrac{\text{dT}}{\text{dr}} \times \left(\text{time} \text{dt}\right)<br /><br />or~ \text{ and } \text{ and } \text{ and } \dfrac{\text{dQ}}{\text{dt}} = - \text{K} \times \left(4 \pir^{2}\right)\dfrac{\text{dT}}{\text{dr}}

∴∴ Radial rate of flow dQdt=P=−4πKr2dTdr\dfrac{\text{d}\text{Q}}{dt} =P = - 4\pi\text{K}r^{2}\dfrac{dT}{dr}

∴∴~ & & P∫r1r2drr2=−4πK∫T1T2dTP\mathop{∫}_{\text{r}1}^{\text{r}2}\dfrac{dr}{\text{r}2} = -4\pi\text{K}\mathop{∫}_{\text{T}1}^{\text{T}2}\text{dT}

or P[r1−r2r1r2]=4πK[T2−T1]<br><br>orP \left[\dfrac{{r}_{1} - {r}_{2}}{{r}_{1}{r}_{2}}\right] =4\pi\text{K}\left[{T}_{2} - {T}_{1}\right]<br><br>orP = 4πK(T1−T2)r1r2(r2−r1)<br/><br/>4\pi\text{K} \left({T}_{1} - {T}_{2}\right){r}_{1}{r}_{2}\left({r}_{2} - {r}_{1}\right)<br /><br />∴ dQdtisproportionalto(r1r2r2−r1).~ \dfrac{\text{d}\text{Q}}{dt}is proportional to \left(\dfrac{{r}_{1} {r}_{2}}{{r}_{2} - {r}_{1}}\right) .
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