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N 2 and O 2 are converted to monopositive cations N 2 + and O 2 + respectively. Which is incorrect? (According to Molecular orbital theory)

Options

  1. AN 2 + becomes diamagnetic
  2. BIn O 2 + , paramagnetism decreases
  3. CIn O 2 + , the bond order increases
  4. DIn N 2 + the N-N bond is weakened.

Correct answer

A. N 2 + becomes diamagnetic

Step-by-step solution

M.O. configuration of N 2 is σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < π 2 p x 2 = π 2 p y 2 < σ 2 p z 2 B.O. of N 2 = 10 - 4 2 = 3 M.O. configuration of N 2 + is σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < π 2 p x 2 = π 2 p y 2 < σ 2 p z 1 B.O. of N 2 + = 9 - 4 2 = 2.5 M.O. of configuration of O 2 is σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < σ 2 p z 2 < π 2 p x 2 < π 2 p y 2 < π * 2 p x 1 < π * 2 p y 1 ∴ B.O. of O 2 = 10 – 6 2 = 2 As it is paramagnetic so option ( a ) is incorrect. M.O. configuration of O 2 +

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