NTA Abhyas NEET2020ChemistryChemical Bonding and Molecular StructurePractice
The bond length in O 2 + , O 2 , O 2 - and O 2 2 - follows the order
Options
- AO 2 2 - > O 2 - > O 2 > O 2 +
- BO 2 + > O 2 > O 2 - < O 2 2 -
- CO 2 > O 2 - > O 2 2 - > O 2 +
- DO 2 - > O 2 2 - > O 2 + > O 2
Correct answer
A. O 2 2 - > O 2 - > O 2 > O 2 +
Step-by-step solution
O 2 - 2 = σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < σ 2 p x 2 < π 2 p y 2 = π 2 p z 2 < π * 2 p y 2 = π * 2 p z 2 B . O . = n b - n a 2 = 6 - 4 2 = 1 O 2 - = σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < σ 2 p x 2 < π 2 p y 2 = π 2 p z 2 < π * 2 p y 2 = π * 2 p z 1 B . O . = 6 - 3 2 = 1.5 O 2 = σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < σ 2 p x 2 < π 2 p z 2 = π 2 p y 2 < π * 2 p y 1 = π * 2 p z 1 B . O . = 6 - 2 2 = 2 O 2 + = σ 1 s 2 < σ * 1 s 2 < σ 2 s 2 < σ * 2 s 2 < σ 2 p x 2 < π 2 p z 2 = π 2 p y 2 < π * 2 p