NTA Abhyas NEET2020ChemistryChemical Bonding and Molecular StructurePractice
For the following pattern of hybridization shown by the central atom, sp, sp 2 , sp 3 1 2 3 sp 3 d 4 which of the following options represent the correct sequence of hybridisation, i.e. according to the sequence mentioned above?
Options
- AH 2 O , C O 2 , B F 3 , P C l 5
- BC O 2 , H 2 O , B F 3 , P C l 5
- CC O 2 , B F 3 , H 2 O , P C l 5
- DH 2 O , C O 2 , P C l 5 , B F 3
Correct answer
C. C O 2 , B F 3 , H 2 O , P C l 5
Step-by-step solution
The orbitals of the central atom that goes for hybridization are: a Orbitals used for a σ bond formation b Orbitals that contain l p (lone pair) of electrons c If required empty orbitals Note: Orbitals involved in π -bond formation and having odd electron will not get hybrid. Thus, Molecule Hybridisation Number of σ bonds + l p C O 2 s p (number of σ bonds = 0 number of l p of electrons = 0 ) B F 3 s p 2 (number of σ bonds = 3 number of l p of electrons = 0 ) H 2 O s p 3 (number of σ bonds = 2 number of l p of elec