If the dipole moment of AB molecule is given by 1.6 D and A–B the bond length is 1 A o then % covalent character of the bond is

Step-by-step solution

μ C a l = 4.8 × 1 0 - 10 e . s . u × 1 0 - 8 c m 4.8 × 10 − 18   esu   ×   cm = 4.8 D Hence, %   ionic   character   =   1 .6 4 .8   ×   100 = 33.33 %