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JEE Mathematics 2015 previous year questions with solutions

87 JEE Mathematics questions from 2015 in the Quantrex bank. Featured questions below open unique solution pages. Browse by chapter on JEE Mathematics.

87 questions2015
1

Let f , g : - 1 , 2 → R be continuous functions which are twice differentiable on the interval - 1 , 2 . Let the values of f and g at the points - 1 , 0 a

JEE Advanced 2015 Application of Derivatives Solution View → 2

Paragraph: Let F: R R be a thrice differentiable function. Suppose that F(1)=0, F(3)=-4 and F^ (x) Question: The correct statement(s) is(are)

JEE Advanced 2015 Application of Derivatives Solution View → 3

A cylindrical container is to be made from certain solid material with the following constraints: It has a fixed inner volume of V m m 3 , has a 2 mm thick soli

JEE Advanced 2015 Application of Derivatives Solution View → 4

The area (in square units) of the region bounded by the curves y + 2 x 2 = 0 and y + 3 x 2 = 1 , is equal to

JEE Main 2015 Area Under Curves Solution View → 5

The area (in sq. units) of the region described by x , y : y 2 ≤ 2 x and y ≥ 4 x - 1 is

JEE Main 2015 Area Under Curves Solution View → 6

The coefficient of x 9 in the expansion of 1 + x   1 + x 2   1 + x 3 … … 1 + x 100 is

JEE Advanced 2015 Binomial Theorem Solution View → 7

If a circle passing through the point - 1 , 0 touches y -axis at 0 , 2 , then the x -intercept of the circle is

JEE Main 2015 Circle Solution View → 8

If the incentre of an equilateral triangle is 1 , 1 and the equation of its one side is 3 x + 4 y + 3 = 0 , then the equation of the circumcircle of this triang

JEE Main 2015 Circle Solution View → 9

If y + 3 x = 0 is the equation of a chord of the circle x 2 + y 2 - 30 x = 0 , then the equation of the circle with this chord as diameter is :

JEE Main 2015 Circle Solution View → 10

Let the tangents drawn to the circle, x 2 + y 2 = 16 from the point P 0 , h meet the x -axis at points A and B . If the area of Δ A P B is minimum, then po

JEE Main 2015 Circle Solution View → 11

The number of common tangents to the circles x 2 + y 2 - 4 x - 6 y - 1 2 = 0 and x 2 + y 2 + 6 x + 1 8 y + 26 = 0 , is

JEE Main 2015 Circle Solution View → 12

For any integer k , let α k = cos ⁡ k π 7 + i sin ⁡ k π 7 , w h e r e i = - 1 . The value of the expression ∑ k = 1 12 α k

JEE Advanced 2015 Complex Number Solution View → 13

Let g : R → R be a differentiable function with g 0 = 0 , g ′ 0 = 0 and g ′ 1 ≠ 0 . Let f x = x | x | g x , x ≠ 0 0 , x = 0 and h

JEE Advanced 2015 Continuity and Differentiability Solution View → 14

Let k be a non - zero real number. If f x = ( e x − 1 ) 2 sin   x k log   1 + x 4 , x   ≠   0 12       &#8

JEE Main 2015 Continuity and Differentiability Solution View → 15

If the function g x = k x + 1 , 0 ≤ x ≤ 3 m x + 2 , 3 < x ≤ 5 is differentiable, then the value of k + m is

JEE Main 2015 Continuity and Differentiability Solution View → 16

If α = ∫ 0 1 e 9 x + 3 tan - 1 ⁡ x 12 + 9 x 2 1 + x 2 d x where tan - 1 ⁡ x takes only principal values, then the value of log e ⁡

JEE Advanced 2015 Definite Integration Solution View → 17

The option(s) with the value of a and L that satisfy the following equation is(are) ∫ 0 4 π e t sin 6 ⁡ a t + cos 4 ⁡ a t d t ∫ 0 &

JEE Advanced 2015 Definite Integration Solution View → 18

Let f x = 7 tan 8 ⁡ x + 7 tan 6 ⁡ x - 3 tan 4 ⁡ x - 3 tan 2 ⁡ x for all x ∈ - π 2 , π 2 . Then the correct expression(S)

JEE Advanced 2015 Definite Integration Solution View → 19

Let f ′ x = 192 x 3 2 + sin 4 ⁡ π x for all x ∈ R with f 1 2 = 0 . If m ≤ ∫ 1 2 1 f x d x ≤ M , then the possible value

JEE Advanced 2015 Definite Integration Solution View → 20

Let F : R → R be a thrice differentiable function. Suppose that F 1 = 0 , F 3 = - 4 and F ′ x < 0 all x ∈ 1 2 , 3 . Let f x = x F ( x ) fo

JEE Advanced 2015 Definite Integration Solution View → 21

Let f : R → R be a function defined by f x = x , x ≤ 2 0 , x > 2 , where [ x ] is the greatest integer less than or equal to x . If I = ∫

JEE Advanced 2015 Definite Integration Solution View → 22

Let F x =   ∫ x x 2 + π 6 2 cos 2 ⁡ t   d t for all x   ∈ R   a n d   f   :   0 , 1 2 → 0 , &#16

JEE Advanced 2015 Definite Integration Solution View → 23

Which of the following values of α satisfy the equation 1 + α 2 1 + 2 α 2 1 + 3 α 2 2 + α 2 2 + 2 α 2 2 + 3 α 2 3 + α 2

JEE Advanced 2015 Determinants Solution View → 24

If x 2 + x x + 1 x - 2 2 x 2 + 3 x - 1 3 x 3 x - 3 x 2 + 2 x + 3 2 x - 1 2 x - 1 = a x - 12 , then a is equal to:

JEE Main 2015 Determinants Solution View →

Other years

2014 · 1182016 · 882017 · 882018 · 1302019 · 3492020 · 1,1412021 · 6632022 · 6502023 · 7522024 · 6342025 · 5072026 · 509
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