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JEE Mathematics 2021 previous year questions with solutions

663 JEE Mathematics questions from 2021 in the Quantrex bank. Featured questions below open unique solution pages. Browse by chapter on JEE Mathematics.

663 questions2021
1

Let f₁:(0, ) R and f₂:(0, ) R be defined by f₁(x)= ₀^ x _ j=1 ²¹(t-j)^ j d t, x>0 and f₂(x)=98(x-1)⁵⁰-600(x-1)⁴⁹+2450, x>0 where, for any positive integer n and

JEE Advanced 2021 Application of Derivatives Solution
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2

Let f₁:(0, ) R and f₂:(0, ) R be defined by f₁(x)= ₀^ x _ j=1 ²¹(t-j)^ j d t, x > 0 and f₂(x)=98(x-1)⁵⁰-600(x-1)⁴⁹+2450, x > 0 where, for any positive integer n

JEE Advanced 2021 Application of Derivatives Solution
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3

Paragraph: Let ₁:[0, ) R , ₂:[0, ) R , f:[0, ) R and g:[0, ) R be functions such that f(0)=g(0)=0 , ₁(x)=e^ -x +x, x 0 , ₂(x)=x²-2 x-2 e^ -x +2, x 0 , f(x)= _ -

JEE Advanced 2021 Application of Derivatives Solution
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4

Paragraph: Let ₁:[0, ) R , ₂:[0, ) R , f:[0, ) R and g:[0, ) R be functions such that f(0)=g(0)=0 , ₁(x)=e^ -x +x, x 0 , ₂(x)=x²-2 x-2 e^ -x +2, x 0 , f(x)= _ -

JEE Advanced 2021 Application of Derivatives Solution
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5

Let f : R → R be defined by f x = x 2 - 3 x - 6 x 2 + 2 x + 4 Then which of the following statements is(are) TRUE?

JEE Advanced 2021 Application of Derivatives Solution
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6

The function f x = x 3 - 6 x 2 + a x + b is such that f 2 = f 4 = 0 . Consider two statements: S 1 there exists x 1 , x 2 ∈ 2 , 4 , x 1 < x 2 , such t

JEE Main 2021 Application of Derivatives Solution
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7

An angle of intersection of the curves, x 2 a 2 + y 2 b 2 = 1 and x 2 + y 2 = a b , a > b , is :

JEE Main 2021 Application of Derivatives Solution
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8

Let f be any continuous function on 0 , 2 and twice differentiable on 0 , 2 . If f 0 = 0 , f 1 = 1 and f 2 = 2 , then :

JEE Main 2021 Application of Derivatives Solution
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9

Let f x be a cubic polynomial with f 1 = - 10 , f - 1 = 6 , and has a local minima at x = 1 , and f ' x has a local minima at x = - 1 . Then f 3 is equal to .

JEE Main 2021 Application of Derivatives Solution
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10

The number of real roots of the equation e 4 x + 2 e 3 x - e x - 6 = 0 is :

JEE Main 2021 Application of Derivatives Solution
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11

If R is the least value of a such that the function f x = x 2 + a x + 1 is increasing on [ 1 , 2 ] and S is the greatest value of a such that the function f ( x

JEE Main 2021 Application of Derivatives Solution
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12

A box open from top is made from a rectangular sheet of dimension a × b by cutting squares each of side x from each of the four corners and folding up the

JEE Main 2021 Application of Derivatives Solution
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13

Let M and m respectively be the maximum and minimum values of the function f ( x ) = tan - 1 ( sin x + cos x ) in 0 , π 2 . Then the value of tan ( M - m )

JEE Main 2021 Application of Derivatives Solution
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14

A wire of length 20 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a regular hexagon. Then the length of the s

JEE Main 2021 Application of Derivatives Solution
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15

The number of distinct real roots of the equation 3 x 4 + 4 x 3 - 12 x 2 + 4 = 0 is _________.

JEE Main 2021 Application of Derivatives Solution
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16

The local maximum value of the function, f x = 2 x x 2 , x > 0 , is

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17

A wire of length 36 m is cut into two pieces, one of the pieces is bent to form a square and the other is bent to form a circle. If the sum of the areas of the

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18

Let f : a , b → R be twice differentiable function such that f x = ∫ a x g t d t for a differentiable function g x . If f x = 0 has exactly five dis

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19

If a rectangle is inscribed in an equilateral triangle of side length 2 2 as shown in the figure, then the square of the largest area of such a rectangle is ___

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20

Let a curve y = f x pass through the point 2 , log e 2 2 and have slope 2 y x log e x for all positive real values of x . Then the value of f e is equal to ____

JEE Main 2021 Application of Derivatives Solution
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21

Let f x = 3 sin 4 x + 10 sin 3 x + 6 sin 2 x - 3 , x ∈ - π 6 , π 2 . Then, f is :

JEE Main 2021 Application of Derivatives Solution
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22

The number of real roots of the equation e 6 x - e 4 x - 2 e 3 x - 12 e 2 x + e x + 1 = 0 is:

JEE Main 2021 Application of Derivatives Solution
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23

Let f : R → R be defined as f x = - 4 3 x 3 + 2 x 2 + 3 x , x > 0 3 x e x , x ≤ 0 . Then f is increasing function in the interval

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24

The sum of all the local minimum values of the twice differentiable function f : R → R defined by f x = x 3 - 3 x 2 - 3 f " ( 2 ) 2 x + f " 1 is:

JEE Main 2021 Application of Derivatives Solution
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