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JEE Mathematics 2019 previous year questions with solutions

349 JEE Mathematics questions from 2019 in the Quantrex bank. Featured questions below open unique solution pages. Browse by chapter on JEE Mathematics.

349 questions2019
1

Let f x = sin ⁡ π x x 2 , x > 0 . Let x 1 < x 2 < x 3 < … < x n < … be all the points of local maximum of f and y

JEE Advanced 2019 Application of Derivatives Solution
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2

Let f : R → R be given by f x = x - 1 x - 2 x - 5 . Define F x = ∫ 0 x f t d t , x > 0 . Then which of the following options is/are correct?

JEE Advanced 2019 Application of Derivatives Solution
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3

Let f : R → R be given by f x = x 5 + 5 x 4 + 10 x 3 + 10 x 2 + 3 x + 1 , x < 0 ; x 2 - x + 1 , 0 ≤ x < 1 ; 2 3 x 3 - 4 x 2 + 7 x - 8 3 , 1

JEE Advanced 2019 Application of Derivatives Solution
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4

The area of the region x , y : x y ≤ 8 , 1 ≤ y ≤ x 2 is

JEE Advanced 2019 Area Under Curves Solution
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5

If the area (in sq. units) bounded by the parabola y 2 = 4 λ x and the line y = λ x ,   λ > 0 , is 1 9 , then λ is equal to

JEE Main 2019 Area Under Curves Solution
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6

If the area (in sq. units) of the region x , y : y 2 ≤ 4 x , x + y ≤ 1 , x ≥ 0 , y ≥ 0 is a 2 + b , then a - b is equal to

JEE Main 2019 Area Under Curves Solution
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7

The area (in sq. units) of the region bounded by the curves y = 2 x and y = x + 1 , in the first quadrant is

JEE Main 2019 Area Under Curves Solution
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8

The region represented by x - y ≤ 2 and x + y ≤ 2 is bounded by a

JEE Main 2019 Area Under Curves Solution
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9

The area (in sq. units) of the region A = x , y : y 2 2 ≤ x ≤ y + 4 is:

JEE Main 2019 Area Under Curves Solution
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10

The area (in sq. units) of the region A = x , y : x 2 ≤ y ≤ x + 2 is

JEE Main 2019 Area Under Curves Solution
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11

Let S α = x , y : y 2 ≤ x , 0 ≤ x ≤ α and A α is area of the region S α . If for a λ , 0 < λ < 4 , A &#9

JEE Main 2019 Area Under Curves Solution
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12

The area (in sq. units) of the region A = x , y ∈ R × R 0 ≤ x ≤ 3 , 0 ≤ y ≤ 4 , y ≤ x 2 + 3 x is

JEE Main 2019 Area Under Curves Solution
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13

The area (in sq. units) of the region bounded by the parabola, y = x 2 + 2 and the lines, y = x + 1 , x = 0 and x = 3 , is

JEE Main 2019 Area Under Curves Solution
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14

The area (in sq. units) in the first quadrant bounded by the parabola, y=x²+1 , the tangent to it at the point (2,5) and the coordinate axes is :

JEE Main 2019 Area Under Curves Solution
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15

The area (in sq. units) of the region bounded by the curve x²=4 y and the straight line x=4 y-2 is :

JEE Main 2019 Area Under Curves Solution
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16

If the area enclosed between the curves y = k x 2 and x = k y 2 , k > 0 , is 1 s q . u n i t . Then k is

JEE Main 2019 Area Under Curves Solution
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17

The area of the region A = x , y : 0 ≤ y ≤ x x + 1 and - 1 ≤ x ≤ 1 in sq. units, is

JEE Main 2019 Area Under Curves Solution
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18

The area (in sq. units) bounded by the parabola y = x 2 - 1 , the tangent at the point 2 , 3 to it and the y -axis is

JEE Main 2019 Area Under Curves Solution
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19

Suppose det ⁡ ∑ k = 0 n k ∑ k = 0 n C k   n k 2 ∑ k = 0 n C k   n k ∑ k = 0 n C k   n 3 k = 0 , holds for some posi

JEE Advanced 2019 Binomial Theorem Solution
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20

If   20 C 1 + ( 2 2 )     20 C 2 + ( 3 2 )   20 C 3 + . . . . . + 20 2     20 C 20 = A 2 β , then the ordered pair ( A

JEE Main 2019 Binomial Theorem Solution
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21

The term independent of x in the expansion of 1 60 - x 8 81 . 2 x 2 - 3 x 2 6 is equal to

JEE Main 2019 Binomial Theorem Solution
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22

The coefficient of x 18 in the product 1 + x 1 - x 10 1 + x + x 2 9 is

JEE Main 2019 Binomial Theorem Solution
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23

The smallest natural number n , such that the coefficient of x in the expansion of x 2 + 1 x 3 n is C 23 n , is

JEE Main 2019 Binomial Theorem Solution
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24

If the coefficients of x 2 and x 3 , are both zero, in the expansion of the expression 1 + a x + b x 2 1 - 3 x 15 , in powers of x , then the ordered pair a , b

JEE Main 2019 Binomial Theorem Solution
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