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JEE Mathematics 2017 previous year questions with solutions

88 JEE Mathematics questions from 2017 in the Quantrex bank. Featured questions below open unique solution pages. Browse by chapter on JEE Mathematics.

88 questions2017
1

If f : R → R is a twice differentiable function such that f ′ ′ x > 0 for all x ∈ R and f 1 2 = 1 2 , f 1 = 1 then

JEE Advanced 2017 Application of Derivatives Solution
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2

If f x = cos ⁡ 2 x cos ⁡ 2 x sin ⁡ 2 x - cos ⁡ x cos ⁡ x - sin ⁡ x sin ⁡ x sin ⁡ x cos ⁡ x , then

JEE Advanced 2017 Application of Derivatives Solution
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3

Let f : R → 0 , 1 , be a continuous function then, which of the following function(s), has(have) the values zero at some point in the interval, (0,1)?

JEE Advanced 2017 Application of Derivatives Solution
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4

Let f x = x + log e ⁡ x - x log e ⁡ x , x ∈ 0 , ∞ • Column 1 contains information about zeros of f ( x ) , f ' ( x ) and f &#3

JEE Advanced 2017 Application of Derivatives Solution
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5

Let f x = x + log e ⁡ x - x log e ⁡ x , x ∈ 0 , ∞ . • Column 1 contains information about zeros of f x , f ′ x and f ′

JEE Advanced 2017 Application of Derivatives Solution
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6

Let f x = x + log e ⁡ x - x log e ⁡ x , x ∈ 0 , ∞ . • Column 1 contains information about zeros of f x , f ′ x and f ′

JEE Advanced 2017 Application of Derivatives Solution
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7

If the line x = α divides the area of the region R = x , y ∈ R 2 : x 3 ≤ y ≤ x , 0 ≤ x ≤ 1 into two equal parts, then

JEE Advanced 2017 Area Under Curves Solution
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8

The area (in sq. units) of the smaller portion enclosed between the curves, x 2 + y 2 = 4 and y 2 = 3 x , is:

JEE Main 2017 Area Under Curves Solution
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9

The area (in sq. units) of the region x , y : x ≥ 0 , x + y ≤ 3 , x 2 ≤ 4 y a n d y ≤ 1 + x is

JEE Main 2017 Area Under Curves Solution
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10

For how many values of p , the circle x 2 + y 2 + 2 x + 4 y - p = 0 and the coordinate axes have exactly three common points?

JEE Advanced 2017 Circle Solution
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11

A line drawn through the point P 4 , 7 cuts the circle x 2 + y 2 = 9 at the points A and B . Then P A · P B is equal to.

JEE Main 2017 Circle Solution
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12

If two parallel chords of a circle, having diameter 4 units, lie on the opposite sides of the center and subtend angles cos - 1 ⁡ 1 7 and sec - 1 ⁡

JEE Main 2017 Circle Solution
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13

If the common tangents to the parabola, x 2 = 4 y and the circle, x 2 + y 2 = 4 intersect at the point P , then the distance of P from the origin (units), is:

JEE Main 2017 Circle Solution
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14

If a point P 0 , - 2 and Q is any point on the circle, x 2 + y 2 - 5 x - y + 5 = 0 , then the maximum value of P Q 2 is

JEE Main 2017 Circle Solution
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15

The radius of a circle, having minimum area, which touches the curve y = 4 - x 2 and the lines, y = x is:

JEE Main 2017 Circle Solution
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16

Let a , b , x and y be real numbers such that a - b = 1 and y ≠ 0 . If the complex number z = x + i y satisfies I m a z + b z + 1 = y , then which of the

JEE Advanced 2017 Complex Number Solution
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17

The equation I m i z - 2 z - i + 1 = 0 , z ∈ C , z ≠ i represents a part of a circle having radius equal to :

JEE Main 2017 Complex Number Solution
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18

Let z ∈ C , the set of complex numbers. Then the equation, 2 z + 3 i - z - i = 0 represents:

JEE Main 2017 Complex Number Solution
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19

Let ω be a complex number such that 2 ω + 1 = z where z = - 3 . If 1 1 1 1 - ω 2 - 1 ω 2 1 ω 2 ω 7 = 3 k , Then k can be equal to:

JEE Main 2017 Complex Number Solution
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20

Let x be the greatest integer less than or equals to x . Then, at which of the following point(s) the function f x = x cos ⁡ π x + x is discontinuous

JEE Advanced 2017 Continuity and Differentiability Solution
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21

The value of k which the function f x = 4 5 tan ⁡ 4 x tan ⁡ 5 x , 0 < x < π 2 k + 2 5 , x = π 2 is continuous at x = π 2 , is

JEE Main 2017 Continuity and Differentiability Solution
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22

The value of I = ∑ k = 1 98 ∫ k k + 1 k + 1 x ( x + 1 ) d x , then

JEE Advanced 2017 Definite Integration Solution
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23

If g x = ∫ sin x sin 2 x sin - 1 t d t , then

JEE Advanced 2017 Definite Integration Solution
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24

Let f   :   R → R be a differentiable function such that f 0 = 0 ,   f π 2 = 3 and f ′ 0 = 1 . If g x = ∫ x π 2 &#160

JEE Advanced 2017 Definite Integration Solution
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