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JIPMER 2010
Exam
JIPMER
Year
2010
Subject
Physics
Chapter
Mechanical Properties of Solids

JIPMER 2010 · Physics · Mechanical Properties of Solids

A cube of side 40 mm has its upper face displaced by 0.1 mm by a...

A cube of side 40 mm has its upper face displaced by 0.1 mm by a tangential force of 8 kN . The shearing modulus of cube is

Options

  1. A2×109Nm−22 \times 10^9 \mathrm{Nm}^{-2}
  2. B4×109Nm−24 \times 10^9 \mathrm{Nm}^{-2}
  3. C8×109Nm−28 \times 10^9 \mathrm{Nm}^{-2}
  4. D16×109Nm−216 \times 10^9 \mathrm{Nm}^{-2}

Correct answer

A. 2×109Nm−22 \times 10^9 \mathrm{Nm}^{-2}

Step-by-step solution

Shearing modulus of cube η=FlAΔl=8×103×40×10−3(40×10−3)2×(0.1×10−3)=2×109Nm−2\begin{aligned} \eta=\frac{F l}{A \Delta l} & =\frac{8 \times 10^3 \times 40 \times 10^{-3}}{\left(40 \times 10^{-3}\right)^2 \times\left(0.1 \times 10^{-3}\right)} \\ & =2 \times 10^9 \mathrm{Nm}^{-2} \end{aligned}
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