JIPMER2010PhysicsMechanical Properties of Solids
A cube of side 40 mm has its upper face displaced by 0.1 mm by a tangential force of 8 kN . The shearing modulus of cube is
Options
- A2 10^9 Nm ⁻²
- B4 10^9 Nm ⁻²
- C8 10^9 Nm ⁻²
- D16 10^9 Nm ⁻²
Correct answer
A. 2 10^9 Nm ⁻²
Step-by-step solution
Shearing modulus of cube aligned = F l A l & = 8 10^3 40 10⁻³ (40 10⁻³ )^2 (0.1 10⁻³ ) & =2 10^9 Nm ⁻² aligned