NEETPhysicsMagnetic Properties of Matter
What is the force and torque acting on a closely wound solenoid with 2000 turns, a cross-sectional area of 1.6 × 10 -4 m 2 , and carrying a current of 4.0 A, when it is suspended through its center and allowed to turn in a horizontal plane, in the presence of a uniform horizontal magnetic field of 7.5 × 10 -2 T at an angle of 30° with the axis of the solenoid?
Options
- AForce is 0.048 N; torque = 0.048 Nm
- BForce is 0.048 N; torque is zero
- CForce is zero; torque is zero
- DForce is zero; torque = 0.048 Nm
Correct answer
D. Force is zero; torque = 0.048 Nm
Step-by-step solution
Correct Option is : (D) Force is zero; torque = 0.048 Nm