A magnetic material of susceptibility 499 is placed inside a magnetising field of 4000 A m ⁻¹ . The magnetic induction inside the material is: ( ₀ = 4 10⁻⁷ T m A ⁻¹ )

Step-by-step solution

Relative permeability is given by _r = 1 + _m . _r = 1 + 499 = 500 The magnetic induction B inside the material is given by B = H = ₀ _r H . B = (4 10⁻⁷) 500 4000 B = 4 10⁻⁷ 2 10^6 = 0.8 T Answer: 0.8 T