A student performs an experiment to determine the magnetic moment of a bar magnet of moment of inertia I . She suspends the magnet in a uniform magnetic field B and measures its time period of oscillation T . She then

Question

Quantrex Academy · Accepted Answer

Correct answer: A. (4π^2 I)/(S)

The time period of a magnetic dipole oscillating in a uniform magnetic field is given by:

T = 2\pi \sqrt{\dfrac{I}{MB}}

Squaring both sides, we get:

T^2 = \dfrac{4\pi^2 I}{M} \left(\dfrac{1}{B}\right)

Comparing this with the equation of a straight line passing through the origin,

y = Sx

, where

y = T^2

and

x = \dfrac{1}{B}

, the slope

S

is:

S = \dfrac{4\pi^2 I}{M}

Rearranging the expression to solve for the magnetic moment

M

:

M = \dfrac{4\pi^2 I}{S}

Answer:

\dfrac{4\pi^2 I}{S}

A student performs an experiment to determine the magnetic moment...

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