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Match List-I with List-II regarding the ratio of the magnitudes of electric field intensity ( E ) to the magnetic field intensity ( H ) for an electromagnetic wave propagating in different media. (Given: ₀ ₀ = 120 ) List-I (Medium properties) List-II ( E/H ratio) (A) Vacuum ( _r=1, _r=1 ) (I) 40 (B) Medium A ( _r=2, _r=8 ) (II) 60 (C) Medium B ( _r=4, _r=1 ) (III) 120 (D) Medium C ( _r=1, _r=9 ) (IV) 240 Choose the c

Options

  1. A(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  2. B(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  3. C(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  4. D(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

Correct answer

C. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Step-by-step solution

The ratio of electric field intensity to magnetic field intensity is given by E/H = = ₀ _r ₀ _r = 120 _r _r . For Vacuum: E/H = 120 1 1 = 120 For Medium A: E/H = 120 2 8 = 120 1 2 = 60 For Medium B: E/H = 120 4 1 = 120 2 = 240 For Medium C: E/H = 120 1 9 = 120 1 3 = 40 Therefore, the correct matching is (A)-(III), (B)-(II), (C)-(IV), (D)-(I). Answer: (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

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