Match List-I with List-II regarding the ratio of the magnitudes of electric field intensity ( E ) to the magnetic field intensity ( H ) for an electromagnetic wave propagating in different media. (Given: (μ_0)/( _0) =

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Correct answer: C. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

The ratio of electric field intensity to magnetic field intensity is given by

E/H = \sqrt{\dfrac{\mu}{\varepsilon}} = \sqrt{\dfrac{\mu_0 \mu_r}{\varepsilon_0 \varepsilon_r}} = 120\pi \sqrt{\dfrac{\mu_r}{\varepsilon_r}}

.

For Vacuum:

E/H = 120\pi \sqrt{\dfrac{1}{1}} = 120\pi

For Medium A:

E/H = 120\pi \sqrt{\dfrac{2}{8}} = 120\pi \times \dfrac{1}{2} = 60\pi

For Medium B:

E/H = 120\pi \sqrt{\dfrac{4}{1}} = 120\pi \times 2 = 240\pi

For Medium C:

E/H = 120\pi \sqrt{\dfrac{1}{9}} = 120\pi \times \dfrac{1}{3} = 40\pi

Therefore, the correct matching is (A)-(III), (B)-(II), (C)-(IV), (D)-(I).

Answer: (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

List-I (Medium properties)	List-II ( $E/H$ ratio)
(A) Vacuum ( $\mu_r=1, \varepsilon_r=1$ )	(I) $40\pi$
(B) Medium A ( $\mu_r=2, \varepsilon_r=8$ )	(II) $60\pi$
(C) Medium B ( $\mu_r=4, \varepsilon_r=1$ )	(III) $120\pi$
(D) Medium C ( $\mu_r=1, \varepsilon_r=9$ )	(IV) $240\pi$

Match List-I with List-II regarding the ratio of the magnitudes of...

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