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Exam
NEET
Subject
Physics
Chapter
Magnetic Properties of Matter

NEET · Physics · Magnetic Properties of Matter

A paramagnetic sample has a relative permeability of 1.0006 at an...

A paramagnetic sample has a relative permeability of 1.00061.0006 at an absolute temperature of 300 K300\text{ K}. What will be its relative permeability at 200 K200\text{ K}?

Options

  1. A1.00041.0004
  2. B1.50091.5009
  3. C1.00091.0009
  4. D0.00090.0009

Correct answer

C. 1.00091.0009

Step-by-step solution

The relative permeability (μr\mu_r) of a magnetic material is related to its magnetic susceptibility (χ\chi) by the relation:
μr=1+χ\mu_r = 1 + \chi

At T1=300 KT_1 = 300\text{ K}, the initial susceptibility is:
χ1=μr1−1=1.0006−1=0.0006\chi_1 = \mu_{r1} - 1 = 1.0006 - 1 = 0.0006

According to Curie's law for paramagnetic materials, susceptibility is inversely proportional to absolute temperature (χ∝1T\chi \propto \dfrac{1}{T}).

Therefore, the ratio of susceptibilities is:
χ2χ1=T1T2\dfrac{\chi_2}{\chi_1} = \dfrac{T_1}{T_2}

χ2=χ1×T1T2=0.0006×300200\chi_2 = \chi_1 \times \dfrac{T_1}{T_2} = 0.0006 \times \dfrac{300}{200}
χ2=0.0006×1.5=0.0009\chi_2 = 0.0006 \times 1.5 = 0.0009

The new relative permeability at T2=200 KT_2 = 200\text{ K} is:
μr2=1+χ2=1+0.0009=1.0009\mu_{r2} = 1 + \chi_2 = 1 + 0.0009 = 1.0009

Answer: 1.00091.0009
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