The angles of dip at the poles and the equator respectively are

Since angle of dip at a place is defined as the angle $\delta$, which is the direction of total intensity of earth's magnetic field $B$ makes with a horizontal line in magnetic meridian, At poles $B=B_V$ and $B_V=B \sin \delta$ \therefore \quad \sin $\delta=$1 \Rightarrow $\delta=$90^{{}^{\circ}} At equator $B=B_H$ and $B_H=B \cos \delta$ \therefore \quad \cos $\delta=$1 \Rightarrow $\delta=$0^{{}^{\circ}} $\text{. }$