Two nuclei, Aluminium ( ^ 27 Al ) and Tellurium ( ^ 125 Te ), have...

The nuclear radius $R$ is related to the mass number $A$ by the empirical formula:

$R = R_0 A^{1/3}$

The ratio of the radii of Aluminium and Tellurium is:

$\dfrac{R_{\text{Al}}}{R_{\text{Te}}} = \left(\dfrac{27}{125}\right)^{1/3} = \dfrac{3}{5}$

Nuclear density is approximately constant for all nuclei and is independent of the mass number $A$. Therefore, the ratio of their nuclear densities is $1:1$.

Answer: $3:5$ and $1:1$