The typical transfer characteristic of a transistor in CE...

The current gain in C-E configuration is given by,

$⇒ \beta = \dfrac{\Delta{I}_{C}}{\Delta{I}_{B}}$

${R}_{C} = 2kΩ, {R}_{B} = 0 . 50kΩ$

Now the voltage gain $= \dfrac{\Delta{I}_{C}{R}_{C}}{\Delta{I}_{B}{R}_{B}} = \dfrac{5 \times {10}^{- 3}}{100 \times {10}^{- 6}} \times \dfrac{2}{0 . 5}$

$= \dfrac{{10}^{- 2}}{5 \times {10}^{- 5}} = \dfrac{1000}{5} = 200$