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An ideal battery of 10 V is connected across two parallel branches. The first branch consists of an ideal p-n junction diode in series with a 5 resistor, where the p-side of the diode is connected to the positive terminal of the battery. The second branch consists of another ideal p-n junction diode in series with a 10 resistor, where the n-side of this diode is connected to the positive terminal of the battery. What

Options

  1. A3 A
  2. B2 A
  3. C1 A
  4. D0.67 A

Correct answer

B. 2 A

Step-by-step solution

The diode in the first branch has its p-side connected to the positive terminal of the battery, so it is forward biased. Being an ideal diode, it acts as a short circuit and offers zero resistance. The diode in the second branch has its n-side connected to the positive terminal of the battery, so it is reverse biased. It acts as an open circuit and offers infinite resistance. Therefore, current only flows through the first branch. The current I supplied by the battery is given by Ohm's law: I = V R = 10 5 = 2 A . A

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