NEETPhysicsSemiconductors
In a logic circuit, two inputs A and B are connected simultaneously to an OR gate and a NAND gate. The outputs of these two gates are then fed as inputs to an AND gate to produce the final output Y . The equivalent logic gate for this entire circuit is:
Options
- AAND gate
- BOR gate
- CXNOR gate
- DXOR gate
Correct answer
D. XOR gate
Step-by-step solution
The output of the OR gate is Y₁ = A + B . The output of the NAND gate is Y₂ = A B . These outputs are fed into an AND gate, so the final output Y is: Y = Y₁ Y₂ Y = (A + B) ( A B ) Using De Morgan's law, A B = A + B . Y = (A + B) ( A + B ) Expanding the expression using the distributive law: Y = A A + A B + B A + B B Since A A = 0 and B B = 0 , we get: Y = A B + A B This is the standard Boolean expression for an XOR gate. Answer: XOR gate