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Match List-I with List-II regarding the total current drawn from a 12 V ideal battery in different circuit configurations containing ideal diodes. List-I (Circuit Configuration) List-II (Total Current) (A) Battery connected in series with a forward-biased diode and a 4 resistor (i) 0 A (B) Battery connected in series with a reverse-biased diode and a 4 resistor (ii) 2 A (C) Battery connected across two parallel branc

Options

  1. A(A)-(iii), (B)-(i), (C)-(ii), (D)-(iv)
  2. B(A)-(iii), (B)-(i), (C)-(iv), (D)-(ii)
  3. C(A)-(i), (B)-(iii), (C)-(iv), (D)-(ii)
  4. D(A)-(iii), (B)-(ii), (C)-(iv), (D)-(i)

Correct answer

B. (A)-(iii), (B)-(i), (C)-(iv), (D)-(ii)

Step-by-step solution

(A) The diode is forward-biased, acting as a short circuit. The equivalent resistance is 4 . Total current I = 12 4 = 3 A . Thus, (A) matches with (iii). (B) The diode is reverse-biased, acting as an open circuit. No current flows. Total current I = 0 A . Thus, (B) matches with (i). (C) Both branches have forward-biased diodes and conduct. The 6 and 3 resistors are in parallel. Equivalent resistance R_ eq = 6 3 6 + 3 = 2 . Total current I = 12 2 = 6 A . Thus, (C) matches with (iv). (D) The branch with the 6 resisto

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