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Match List-I with List-II. List-I (Boolean Expression) List-II (Logic Gate) (P) Y = A B (1) AND (Q) Y = A B (2) OR (R) Y = A + B (3) NAND (S) Y = A + B (4) NOR Choose the correct answer from the options given below:

Options

  1. AP-(2), Q-(4), R-(1), S-(3)
  2. BP-(1), Q-(3), R-(2), S-(4)
  3. CP-(2), Q-(3), R-(1), S-(4)
  4. DP-(1), Q-(4), R-(2), S-(3)

Correct answer

A. P-(2), Q-(4), R-(1), S-(3)

Step-by-step solution

Let us simplify each Boolean expression using De Morgan's laws: (P) Y = A B Applying De Morgan's law ( X Y = X + Y ): Y = A + B = A + B This is the expression for an OR gate. So, P matches with (2). (Q) Y = A B Applying De Morgan's law ( X Y = X + Y ): Y = A + B This is the expression for a NOR gate. So, Q matches with (4). (R) Y = A + B Applying De Morgan's law ( X + Y = X Y ): Y = A B = A B This is the expression for an AND gate. So, R matches with (1). (S) Y = A + B Applying De Morgan's law ( X + Y = X Y ): Y =

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