NEETPhysicsSemiconductors
Match List-I with List-II. List-I (Composite Circuit) List-II (Equivalent Single Gate) (A) Input A to NOT, Input B to NOT, both to AND (I) AND (B) Input A to NOT, Input B to NOT, both to OR (II) OR (C) Inputs A and B to NAND, output to NOT (III) NAND (D) Inputs A and B to NOR, output to NOT (IV) NOR Choose the correct answer from the options given below:
Options
- A(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
- B(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- C(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- D(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
Correct answer
A. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Step-by-step solution
Let us evaluate the Boolean expression for each composite circuit in List-I: (A) Input A to NOT gives A , and Input B to NOT gives B . Feeding both to an AND gate gives Y = A B . By De Morgan's laws, A B = A + B , which is the NOR operation. So, (A) matches with (IV). (B) Input A to NOT gives A , and Input B to NOT gives B . Feeding both to an OR gate gives Y = A + B . By De Morgan's laws, A + B = A B , which is the NAND operation. So, (B) matches with (III). (C) Inputs A and B to a NAND gate gives A B . Passing th