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Match List-I with List-II for rectifier circuits, where V_m is the peak AC voltage across the secondary coil (or half of the secondary coil in case of a center-tap transformer). List-I List-II (A) Average DC voltage across load in half-wave rectifier (I) V_m (B) Average DC voltage across load in full-wave rectifier (II) 2V_m (C) Peak Inverse Voltage (PIV) of diode in half-wave rectifier (III) V_m (D) Peak Inverse Vol

Options

  1. A(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  2. B(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  3. C(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  4. D(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Correct answer

B. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Step-by-step solution

In a half-wave rectifier, the output is present only for one half-cycle. The average DC voltage is given by V_ dc = V_m . In a full-wave rectifier, the output is present for both half-cycles. The average DC voltage is twice that of a half-wave rectifier, given by V_ dc = 2V_m . The Peak Inverse Voltage (PIV) is the maximum reverse voltage a diode must withstand without breaking down. For a half-wave rectifier, the maximum reverse voltage across the non-conducting diode is V_m . For a center-tap full-wave rectifier,

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