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NEET2018PhysicsSemiconductorsActual

If current in diode is five times that in R₁ . Breadkdown voltage of diode is 6 volt. Find the value of R .

Options

  1. A2000
  2. B2000 / 3
  3. C1000
  4. D1000 / 3

Correct answer

B. 2000 / 3

Step-by-step solution

Current in diode is 5 times that in R₁ . Current through R₁ is I₁= V R₁ = 6 1 10^3 ~A =6 ~mA So total current drawn from battery =6 ~mA +30 ~mA =36 ~mA Potential difference across R=24 volt So V=I R ; 24=36 10⁻³ R ; R=2000 / 3

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