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NEET2016PhysicsSemiconductorsActual

A zener diode is specified as having a breakdown voltage of 9.1 ~V , with a maximum power dissipation of 364 ~mW . What is the maximum current the diode can handle?

Options

  1. A40 ~mA
  2. B60 ~mA
  3. C50 ~mA
  4. D45 ~mA

Correct answer

A. 40 ~mA

Step-by-step solution

The maximum permissible current is I_ Z_ = P V_Z = 364 10⁻³ 9.1 =40 ~mA

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