For a common-emitter transistor, input current is 5 A , =100 circuit is operated at load resistance of 10 k , then voltage across collector emitter will be

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Correct answer: A. 5 ~V

Here, I_B=5 A =5 10⁻⁶ ~A =100R_L=10 k =10 10^3 As = I_C I_B or I_C=(100) (5 10⁻⁶ ~A )=5 10⁻⁴ ~A The voltage across collector emitter is V_ C E =R_L I_C= (10 10^3 ) (5 10⁻⁴ ~A )=5 ~V

For a common-emitter transistor, input current is 5 A , =100 circuit is operated at load resistance of 10 k , then voltage across collector emitter will be

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