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NEETChemistryCoordination Compounds

Match the following Column-I Complex Column-II Structure / Geometry / Property (A) Ni CN 4 2 - (I) Tetrahedral / Paramagnetic (B) Ni CO 4 (II) Tetrahedral / Diamagnetic (C) NiCl 4 2 - (III) Square planar / Diamagnetic The correct match is

Options

  1. AA B C II I III
  2. BA B C I. II III
  3. C.A B C III II I
  4. DA B C III I II.

Correct answer

C. .A B C III II I

Step-by-step solution

Ni CN 4 2 - Square planar The electrons are paired in 3 d orbitals because CN - is strong field ligand.Hence the hybridisation will be dsp 2 Ni CO 4 Tetrahedral CO is strong field ligand. First the unpaired electrons will pair and then the electrons from 4 s orbital will go in 3 d orbital. Now 4 s and 4 p is empty hence it will be sp 3 hybridised. NiCl 4 2 is paramagnetic in nature due to presence of 2 unpaired electrons. Ni 2 + ion has 3 d 8 electronic configuration. It undergoes sp 3 hybridisation which results i

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