NEETChemistryCoordination Compounds
Match List I with List II: List I (Complex) List II (CFT condition and spin-only magnetic moment ) (A) [ Fe ( CN )₆ ]³⁻ (I) _ o (B) [ CoF ₆ ]³⁻ (II) _ o > P , = 0 BM (C) [ Mn ( H ₂ O )₆ ]²⁺ (III) _ o > P , = 1.73 BM (D) [ Co ( NH ₃ )₆ ]³⁺ (IV) _ o Choose the correct answer from the options given below:
Options
- AA-III, B-IV, C-I, D-II
- BA-III, B-I, C-IV, D-II
- CA-II, B-IV, C-I, D-III
- DA-IV, B-I, C-II, D-III
Correct answer
B. A-III, B-I, C-IV, D-II
Step-by-step solution
(A) In [ Fe ( CN )₆ ]³⁻ , Fe is in +3 oxidation state ( 3 d ^5 ). CN ⁻ is a strong field ligand, so the crystal field splitting energy is greater than pairing energy ( _ o > P ). Electrons pair up to give a t_ 2g ^5 e_g^0 configuration. It has 1 unpaired electron, so = 1(1+2) = 1.73 BM . (B) In [ CoF ₆ ]³⁻ , Co is in +3 oxidation state ( 3 d ^6 ). F ⁻ is a weak field ligand, so _ o (C) In [ Mn ( H ₂ O )₆ ]²⁺ , Mn is in +2 oxidation state ( 3 d ^5 ). H ₂ O is a weak field ligand, so _ o (D) In [ Co ( NH ₃ )₆ ]³⁺ , C