NEETChemistryCoordination Compounds
Match List-I with List-II. List-I (Complex) List-II (Spin-only magnetic moment) (A) [ Fe(H ₂ O )₆]²⁺ (I) 0 BM (B) [ Mn(H ₂ O )₆]²⁺ (II) 1.73 BM (C) [ Ni(CN) ₄]²⁻ (III) 4.90 BM (D) [ Cu(NH ₃)₄]²⁺ (IV) 5.92 BM Choose the correct answer from the options given below:
Options
- A(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- B(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- C(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- D(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Correct answer
C. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Step-by-step solution
For [ Fe(H ₂ O )₆]²⁺ : Fe is in +2 oxidation state. The electronic configuration of Fe ²⁺ is [ Ar ] 3d^6 . H₂ O is a weak field ligand, so pairing does not occur. The configuration is t_ 2g ^4 e_g^2 . Number of unpaired electrons, n = 4 . = 4(4+2) = 24 4.90 BM. For [ Mn(H ₂ O )₆]²⁺ : Mn is in +2 oxidation state. The electronic configuration of Mn ²⁺ is [ Ar ] 3d^5 . H₂ O is a weak field ligand. The configuration is t_ 2g ^3 e_g^2 . Number of unpaired electrons, n = 5 . = 5(5+2) = 35 5.92 BM. For [ Ni(CN) ₄]²⁻ : Ni