NEETChemistryCoordination Compounds
Match List-I with List-II: List-I List-II A. [ Pt(NH ₃)₆] Cl ₄ (i) 1:2 electrolyte B. K ₃[ Fe(CN) ₆] (ii) 3:1 electrolyte C. [ Co(NH ₃)₅ Cl ] Cl ₂ (iii) Non-electrolyte D. [ Ni(CO) ₄] (iv) 1:4 electrolyte Choose the correct answer from the options given below:
Options
- AA-(ii), B-(iv), C-(i), D-(iii)
- BA-(iv), B-(ii), C-(iii), D-(i)
- CA-(iv), B-(ii), C-(i), D-(iii)
- DA-(i), B-(ii), C-(iv), D-(iii)
Correct answer
C. A-(iv), B-(ii), C-(i), D-(iii)
Step-by-step solution
[ Pt(NH ₃)₆] Cl ₄ dissociates into one [ Pt(NH ₃)₆]⁴⁺ cation and four Cl ⁻ anions, making it a 1:4 electrolyte. K ₃[ Fe(CN) ₆] dissociates into three K ⁺ cations and one [ Fe(CN) ₆]³⁻ anion, making it a 3:1 electrolyte. [ Co(NH ₃)₅ Cl ] Cl ₂ dissociates into one [ Co(NH ₃)₅ Cl ]²⁺ cation and two Cl ⁻ anions, making it a 1:2 electrolyte. [ Ni(CO) ₄] does not dissociate into ions in aqueous solution, so it is a non-electrolyte. Therefore, the correct matching is A-(iv), B-(ii), C-(i), D-(iii). Answer: A-(iv), B-(ii),