Match List I with List II. List I (Ligand) List II (Denticity and Donor Atoms) A. EDTA⁴⁻ I. Bidentate with two O donors B. Oxalate ion II. Unidentate with one N donor C. Ethane-1,2-diamine III. Hexadentate with four O and two N donors D. Ammonia IV. Bidentate with two N donors Choose the correct answer from the options given below:

Step-by-step solution

EDTA⁴⁻ is a hexadentate ligand that binds through four oxygen and two nitrogen donor atoms (A III). Oxalate ion ( C₂O₄²⁻ ) is a bidentate ligand that binds through two oxygen atoms (B I). Ethane-1,2-diamine (en) is a bidentate ligand that binds through two nitrogen atoms (C IV). Ammonia ( NH₃ ) is a unidentate ligand that binds through one nitrogen atom (D II). Therefore, the correct matching is A-III, B-I, C-IV, D-II. Answer: A-III, B-I, C-IV, D-II