NEETChemistryCoordination Compounds
Match List-I with List-II. List-I (Ligand) List-II (Classification) (A) en (I) Ambidentate (B) NCS^- (II) Bidentate (C) EDTA⁴⁻ (III) Hexadentate (D) H₂O (IV) Unidentate Choose the correct answer from the options given below:
Options
- A(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
- B(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
- C(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
- D(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
Correct answer
B. (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
Step-by-step solution
(A) en (ethane-1,2-diamine) has two nitrogen donor atoms and binds through both simultaneously, making it a bidentate ligand. (A)-(II) (B) NCS^- (thiocyanate) has two donor atoms (N and S) but binds through only one at a time, making it an ambidentate ligand. (B)-(I) (C) EDTA⁴⁻ (ethylenediaminetetraacetate) has six donor atoms (two nitrogen and four oxygen atoms) and binds through all six, making it a hexadentate ligand. (C)-(III) (D) H₂O (water) has only one type of donor atom (oxygen) and binds through it, making