NEETChemistryCoordination Compounds
Match List-I with List-II regarding the crystal field electronic configuration of the central metal ion. List-I (Complex Ion) List-II (Electronic Configuration) (A) [Cr(NH₃)₆]³⁺ (I) t_ 2g ^3 e_g^2 (B) [Mn(H₂O)₆]²⁺ (II) t_ 2g ^6 e_g^2 (C) [Fe(CN)₆]³⁻ (III) t_ 2g ^3 e_g^0 (D) [Ni(H₂O)₆]²⁺ (IV) t_ 2g ^5 e_g^0 Choose the correct answer from the options given below:
Options
- A(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- B(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- C(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
- D(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Correct answer
B. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Step-by-step solution
(A) [Cr(NH₃)₆]³⁺ : Cr is in +3 oxidation state. The electronic configuration is d^3 . For a d^3 ion in an octahedral field, the configuration is always t_ 2g ^3 e_g^0 regardless of ligand strength. (Matches III) (B) [Mn(H₂O)₆]²⁺ : Mn is in +2 oxidation state. The electronic configuration is d^5 . H₂O is a weak field ligand ( _o (C) [Fe(CN)₆]³⁻ : Fe is in +3 oxidation state. The electronic configuration is d^5 . CN^- is a strong field ligand ( _o > P ), so it forms a low-spin complex with configuration t_ 2g ^5 e_g^