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NEETChemistryCoordination Compounds

Match List I with List II. List I (Coordination Compound) List II (Classification) (A) [Co(NH₃)₄Cl₂]^+ (I) Homoleptic and Anionic (B) K₃[Fe(CN)₆] (II) Heteroleptic and Neutral (C) [Ni(CO)₄] (III) Homoleptic and Neutral (D) [Pt(NH₃)₂Cl₂] (IV) Heteroleptic and Cationic Choose the correct answer from the options given below:

Options

  1. A(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  2. B(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  3. C(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  4. D(A)-(I), (B)-(IV), (C)-(II), (D)-(III)

Correct answer

A. (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Step-by-step solution

Homoleptic complexes contain only one type of ligand, while heteroleptic complexes contain more than one type of ligand. (A) [Co(NH₃)₄Cl₂]^+ contains two types of ligands ( NH₃ and Cl^- ), so it is heteroleptic. It carries a positive charge, making it cationic. (Matches IV) (B) K₃[Fe(CN)₆] contains only one type of ligand ( CN^- ), so it is homoleptic. The coordination entity is [Fe(CN)₆]³⁻ , which is anionic. (Matches I) (C) [Ni(CO)₄] contains only one type of ligand ( CO ), so it is homoleptic. It carries no char

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