NEETChemistryCoordination Compounds
Match List-I with List-II. List-I (Ligand) List-II (Classification) (A) EDTA ⁴⁻ (I) Monodentate (B) C₂ O₄²⁻ (II) Ambidentate (C) SCN ⁻ (III) Bidentate (D) NH₃ (IV) Hexadentate Choose the correct answer from the options given below:
Options
- A(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- B(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
- C(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- D(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
Correct answer
D. (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
Step-by-step solution
(A) EDTA ⁴⁻ (ethylenediaminetetraacetate) is a hexadentate ligand as it coordinates through two nitrogen and four oxygen atoms. (B) C₂ O₄²⁻ (oxalate) is a bidentate ligand as it coordinates through two oxygen atoms. (C) SCN ⁻ (thiocyanate) is an ambidentate ligand because it can coordinate through either the sulfur or the nitrogen atom. (D) NH₃ (ammonia) is a monodentate ligand as it coordinates through a single nitrogen atom. Therefore, the correct matching is (A)-(IV), (B)-(III), (C)-(II), (D)-(I). Answer: (A)-(I