NEET2016ChemistryCoordination CompoundsActual
In [ CO ( H ₂ O )₆ ]²⁺ , there are three unpaired electrons present. The _ calculated is 3.87 BM which is quite different from the _ experimental of 4.40 BM . This is because of
Options
- Aincrease in number of unpaired electrons
- Bsome contribution of the orbital motion of the electron to the magnetic moment
- Cchange in orbital spin of the electron
- Dd-d transition
Correct answer
B. some contribution of the orbital motion of the electron to the magnetic moment
Step-by-step solution
In [ Co ( H ₂ O )₆ ]²⁺ , there are three unpaired electrons present as, _ cal = n(n+1) BM = 3(3+1) BM =3.87 BM As, the t_ 2 g orbital is unsymmetrically filled hence due to orbital motion contribution, magnetic moment goes with the value 4.40 BM