BITSAT2013MathematicsComplex NumberActual
If and are the roots of x²-x+1=0, then the equation whose roots are ¹⁰⁰ and ¹⁰⁰ are
Options
- Ax²-x+1=0
- Bx²+x-1=0
- Cx²-x-1=0
- Dx²+x+1=0
Correct answer
D. x²+x+1=0
Step-by-step solution
We have x³+1 (x+1) (x²-x+1 ) . Therefore, and are the complex cube roots of -1 so that we may take =- and =- ², where 1 is a cube root of unity. Thus ¹⁰⁰=(- )¹⁰⁰= and ¹⁰⁰= (- ² )¹⁰⁰= ², so that the required equation is x ²+ x +1=0